The length of a rectangle is twice its widith. lf the perimeter of the rectangle is 30 yd, find it's length.

Question

please give me the answer to this problem!

Answer 1

The length of a rectangle is twice its widith. lf the perimeter of the rectangle is 30 yd, find it's length.

Detailed Solution:

Given/Known: L = 2W Perimeter: P = 2L + 2W = 30

P = 2L + 2W = 30 ==> 2(2W) + 2W = 30 ==> 4W + 2W = 30 ==> 6W = 30 ==> W = 5

L = 2W ==> L = 2(5) ==> L = 10

Check: P = 2L + 2W = 30 ==> P = 2(10) + 2(5) = 30 ==> P = 20 + 10 = 30 ==> P = 30 = 30 (True - Checks)

Answer 2

L - length

W - width

L=2W

P=2L + 2W

30=4W+2W

30=6W

W=5

L=10