
Yefim S. answered 04/15/22
Math Tutor with Experience
f(1) = 13 = 1; f'(x) = 3x2; f'(1) = 3; f''(x) = 6x; f''(1) = 6; f'''(1) = 6; f(4)(x) = 0; f(4)(1) = 0.
C0 = 1; C1= 3, C2 = 6/2! = 3; C3 = 6/3! = 1; C4 = 0/4! = 0
Matt M.
asked 04/15/22The Taylor series for f(x)=x3 at 1 is ∑∞N=0 Cn(x-1)n.
Find the first few coefficients.
C0=
C1=
C2=
C3=
C4=
I have no clue how to solve this, help greatly appreciated
Yefim S. answered 04/15/22
Math Tutor with Experience
f(1) = 13 = 1; f'(x) = 3x2; f'(1) = 3; f''(x) = 6x; f''(1) = 6; f'''(1) = 6; f(4)(x) = 0; f(4)(1) = 0.
C0 = 1; C1= 3, C2 = 6/2! = 3; C3 = 6/3! = 1; C4 = 0/4! = 0
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