A couple plans to have three children. The 8 different combinations of girls, and boys, the couple could have are shown below. S= {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

Question

A couple plans to have three children. The 8 different combinations of girls, and boys, the couple could have are shown below.

S= {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

Let A be the event that the first child is a girl and let B be the event that the second child is a girl.

What is P(A)? 

What is P(B)?

Answer 1

P(any event) = Number of times event occurs in the sample space / Number of events in the sample space

P(A) = 4/8 = 1/2

I'll leave P(B) for you.