J.R. S. answered 04/10/22
Ph.D. University Professor with 10+ years Tutoring Experience
CaCO3(s) <==> Ca2+(aq) + CO32-(aq)
Write the Ksp expression (equilibrium expression/equilibrium constant):
Ksp = [Ca2+][CO32-]
Ksp = (x)(x)
Ksp = x2
Koyuki M.
asked 04/09/22CaCO3 calcium carbonate only partially dissolves in an aqueous medium according to the reaction:
(= is supposed to be arrows that go both ways since I can not type that on my laptop)
CaCO3(solid) = Ca^2(aq)+CO3^2-(aq)
Assuming that the initial amount of CaCO3 was 1.0 mole in a 1.0-liter solution and that at equilibrium x moles of CaCO3 have dissolved, which of the following statements is correct?
A. The equilibrium constant of this reaction is X^2/(1-x).
B. The efficiency of this reaction is equal to X^2.
C. The degree of dissociation of this reaction is equal to X/2.
D. The equilibrium constant of this reaction is X^2.
Please help me solve this step by step with an explanation in detail.
Thank you so much
J.R. S. answered 04/10/22
Ph.D. University Professor with 10+ years Tutoring Experience
CaCO3(s) <==> Ca2+(aq) + CO32-(aq)
Write the Ksp expression (equilibrium expression/equilibrium constant):
Ksp = [Ca2+][CO32-]
Ksp = (x)(x)
Ksp = x2
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