For homewok,terrys has to creat an equation of a parabola that has a vertex (-6,12) asn includs point (-10,0).She proceeds with the following steps.

Answer 1

Vertex form of a parabola: y = a(x - h)² + k, where (h,k) is the vertex

So, y = a((x - (-6))² + 12

Since (-10, 0) is on the graph, we have 0 = a(-10 + 6)² + 12

0 = 16a + 12

a = -3/4

y = (-3/4)(x + 6)² + 12