Peter R. answered 04/07/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Here's another (popular) system of equations problem.
Let C = price of cherry pie; L = price of lemon pie. Money from sale = No. pies x price/pie.
For Trevon: 9C + 4L = $104
For Eduardo: 6C + 6L = $126 Need to eliminate one of the variables. Can use substitution by manipulating one of the equations to isolate a variable and inserting the result into the other, or elimination. For this problem I would choose the latter.
One way would be to multiplty the 1st eqn by 3 and the 2nd by -2. This will eliminate the "L" variable.
3(9C + 4L ) = 3(104) -> 27C + 12L = 312
-2(6C + 6L) = -2(126) -> -12C - 12L = -252 Now can add.
15C = 60 C = $4
Now substitute into one of the eqns to find L: 9(4) + 4L = 104 -> 36 + 4L = 104 -> 4L = 68 L = $17
Check: 9(4) + 4(17) = 104? (Yes)
6(4) + 6(17) = 126? (Yes) I'm wondering why lemon pie costs so much more!!

Liz Z.
04/10/22