
Yefim S. answered 04/04/22
Math Tutor with Experience
∑0∞(−2)n / n! ) * (x−3)n.
lim n→∞ I(-2)n+1(x - 3)n+1·n!/[(-2)n(n + 1)!(x-3)n]I = lim n→∞ I2(x-3I/(n+1)I = 0 < 1.
So, series converges for any x: - ∞ < x < ∞
Alyssa R.
asked 04/04/22Find the interval of convergence for the power series
∑n=0∞ ( (−2)^n / n! ) * (x−3)n
Give your answer using interval notation. If you need to use INF. If there is only one point in the interval of convergence, the interval notation is [a]. For example, if 0 is the only point in the interval of convergence, you would answer with [0].
Yefim S. answered 04/04/22
Math Tutor with Experience
∑0∞(−2)n / n! ) * (x−3)n.
lim n→∞ I(-2)n+1(x - 3)n+1·n!/[(-2)n(n + 1)!(x-3)n]I = lim n→∞ I2(x-3I/(n+1)I = 0 < 1.
So, series converges for any x: - ∞ < x < ∞
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