Find the average rate of change for the quadratic function ℎ(𝑡) =− 16𝑡 on 2 + 26𝑡 − 25 the interval [2, 5].

Answer 1

h'(x) = -16t +26

h'(2) = -16(2) +26 = -32 +26 = -6

h'(5) = -16(5) +26 = -80 +26 = - 54

average h'(2) and h'(5) = (-6-54)/2 = -30 = average rate of change in the interval [2,5]

average of 2 and 5 is 3.5

h'(3.5) = -16(3.5) + 26 = -56 +26 = -30