Length and width

Question

14. The area of a playground is 108 yd^2. The width of the playground is 3 yards longer than its length. Find the length and width of the playground

Answer 1

A = LW = (3+L)L = 3L +L^2 = 108

L^2 +3L - 108 = 0

(L+12)(L-9) = 0

L=9 yards long

W = 12 yards wide

Area = 9x12 = 108 yd^2