Hi Thomas,
If 2 and 4 are roots of the quadratic equation, then x-2 and x-4 must be factors of the equation . . . because when solving a factored equation, we would set each factor equal to 0.
x - 2 = 0 means that x = 2; and
x - 4 = 0 means that x = 4.
So, the quadratic equation must be:
f(x) = (x - 2)(x - 4)
f(x) = x^2 - 6x + 8
Now, if the leading coefficient is 3, then we simply need to multiply the whole equation by 3
f(x) = 3x^2 - 18x + 24
which has a factored form that is
f(x) = 3(x - 2)(x - 4)
Hope this helps!
JMJ
Thomas B.
thx so much03/29/22