Finding the 8th term of the geometric progression

Question

Finding the 8th term of the geometric progression : 6, 3, 3/2

Answer 1

nth term of geometric progression = a(n) = a(1) * r^(n-1)

Here n = 8, a(1) = 6 and r = ratio of 2nd term to 1st term = 3/6 = 1/2

plug in those values into the equation to determine a(8)

a(8) = 6 * (1/2)^7 = 0.046875