Raymond B. answered 03/26/22
Math, microeconomics or criminal justice
A/(x+1) + B/(3x+2) = (3x+2)A/(x+1)(3x+2) +(x+1)B/(3x+2)(x+1)
= (3xA +2A + Bx +B)/(3x+2)(x+1)
= [(3xA +Bx) +(2A+B)]/(3x+2)(x+1)
3A +B = 2
2A +B =-1
A = 3
B =-1-2A = -7
A=3, B =--7