In an arithmetic sequence with a₁=-24 and d=8​, which term is ​32?

Question

In an arithmetic sequence with a₁=-24 and d=8​, which term is ​32?

Answer 1

an = -24 +8(n-1)

32 = -24 +8n -8 = -32 +8n

8n = 64

n = 64/8 = 8th term is 32

32 is the 8th term

-24, -16, -8, 0, 8, 16, 24, 32, ....

or if by chance you were asking for the 32nd term then it's 224

a32 = 32nd term in an AP = -24+8(31 248-24 = 224

Answer 2

We can use this equation:

a_n=a₁+(n-1)d

We are looking for the n term, so we can fill in the rest with the given information.

32=-24+(n-1)8

32=-24+8n-8

32=-32+8n

64=8n

n=8

Hope this helps!