Vishal S. answered 03/21/22
Cornell Math Minor with 12 years of Math Tutoring Experience
For this question, we obviously assume that each school is using the same sizes or vans and buses. If we let v be the number of students in each van and b be the number of student on each bus, we know from high school A's information that 11v+7b=459.
Similarly, we know from high school B's information that 16v+10b=660. Let's write these two equations as a system:
11v+7b=459
16v+10b=660
We want to make some variables cancel. Let's multiply the top equation by 10 and the bottom equation by 7 to try and cancel out the b terms.
110v+70b=4590
112v+70b=4620
Subtracting the above equations from each other yields −2v=−30, which means v=15.
Substituting this back into the original top equation,
11(15)+7b=459
7b=459−165
7b=294
b=42
Thus, there are 15 students per van and 42 students per bus!