Vishal S. answered 03/21/22
Math & Science Tutor | Cornell Grad & NYU Medical Student
For this question, we obviously assume that each school is using the same sizes or vans and buses. If we let v be the number of students in each van and b be the number of student on each bus, we know from high school A's information that 11v+7b=459.
Similarly, we know from high school B's information that 16v+10b=660. Let's write these two equations as a system:
11v+7b=459
16v+10b=660
We want to make some variables cancel. Let's multiply the top equation by 10 and the bottom equation by 7 to try and cancel out the b terms.
110v+70b=4590
112v+70b=4620
Subtracting the above equations from each other yields −2v=−30, which means v=15.
Substituting this back into the original top equation,
11(15)+7b=459
7b=459−165
7b=294
b=42
Thus, there are 15 students per van and 42 students per bus!