By trial and error, f(3) = 0, so x - 3 is a factor.
Divide f(x) by x - 3 to get f(x) = (x - 3) (x2 + 6x + 7)
Now use the quadratic formula to determine the roots of x2 + 6x + 7.
Ani B.
asked 03/21/22f(x)=x3+3x2−11x−21, including factors for irrational zeros. Use radicals, not decimal approximations.
By trial and error, f(3) = 0, so x - 3 is a factor.
Divide f(x) by x - 3 to get f(x) = (x - 3) (x2 + 6x + 7)
Now use the quadratic formula to determine the roots of x2 + 6x + 7.
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