Please help me with this

Question

Find the critical numbers of the function. (Enter your answers as a comma-separated list.)

f(x) = 3x² − 8x

x =

Answer 1

Critical numbers are where the function's tangent lines are horizontal. That means we need to find the points where the derivative is equal to 0. So let's first find the derivative:

f'(x) = 6x - 8

Now set it to zero and find x:

6x - 8 = 0

x = 8/6 = 4/3

So 4/3 is the critical point of this function.