The idea is showing it is closed under addition and scalar multiplication.
f(<x,y>) = 2x-9y
f(<x1,y1>+<x2,y2>)= f(<x1+x2, y1+y2>=2(x1+x2)-9(y1+y2)=2x1-9y1+2x2-9y2=f(<x1,y1>)+f(<x2,y2>)
You can verify this step and inlude any steps I may have skipped over.
You can also use the same process to show that the identity (origin) of R2 maps to the identity (zero) of R
and the same for the scalar multiplication. Thus you can make your conculusion