Inactive Tutor answered 05/21/22
V = pir^2h
7r = 5h
r =5h/7
V = pi(5h/7)^2(h)
= 25pi/49)(h^3)
take the derivative of V evaluated when h'=.02 and h=14
V' = (3)(25pi/49)h^2(h')
V' = (75pi/49)(14)^2(.02) = rate of change in Volume
William B.
asked 03/10/22If the volume of the circular cylinder is given with the 𝑽=𝝅𝒓𝟐𝒉 and 𝟕𝒓=𝟓𝒉, if the height increases by 0.02 m/sec, Find the rate of increase in the volume of the cylinder when 𝒉=𝟏𝟒𝒄𝒎
Inactive Tutor answered 05/21/22
V = pir^2h
7r = 5h
r =5h/7
V = pi(5h/7)^2(h)
= 25pi/49)(h^3)
take the derivative of V evaluated when h'=.02 and h=14
V' = (3)(25pi/49)h^2(h')
V' = (75pi/49)(14)^2(.02) = rate of change in Volume
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