Raymond B. answered 03/06/22
Math, microeconomics or criminal justice
6x^3 -7x^2 -3x =0
step 6&7&8 should also have included x=0
step 8 should have had x=3/2, not 2/3
x=-1/3, 0, 3/2
6x^3 -16x^2 -32x=0
2x(3x^2 -8x -16)=0
2x(3x+4)(x-4)=0
2x=0, 3x+4=0, x-4=0
x=0, x=-4/3, x= 4
x= -4/3, 0, 4
9x^2-25 =0
(3x-5)(3x+5)=0
3x-5=0, 3x+5=0
x=5/3, x=-5/3
x = -5/3, 5/3