How many liters of pure alcohol must be added to 10 l of a 20% solution to make a 50% solution

Answer 1

1.00x+ .0.20(10) = 0.50(10+x)

x + 2 = 5 +x/2

x/2 = 3

x = 6 liters of pure alcohol added to 10 liters of 20% yield 16 liters of 50%

20 is within 30 of 50

100 is within 50 of 50

50/30 = 5/3 = 10/6

you need the ratio of 20% to pure to be 5/3. 10/6=5/3