
Mark M. answered 03/05/22
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
P = (6, y)
√[(6 - 8)2 + (0 - y)2] + √[(6 + 8)2 + (0 - y)2] = 20
Noelle S.
asked 03/05/22The sum of distances from a point P to (8,0) and (-8,0) is 20. If the abscissa of P is 6, find the ordinate. I'm a little confused about this problem.
Mark M. answered 03/05/22
Mathematics Teacher - NCLB Highly Qualified
P = (6, y)
√[(6 - 8)2 + (0 - y)2] + √[(6 + 8)2 + (0 - y)2] = 20
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