A merchant wants to make a 10-pound mixture of two kinds of candy m&M's cost $1.20 per pound Reese's cost $1.20 per pound how many pounds of each should used if the total 10 lb makes your cost $15.90

Answer 1

15.90/10 = $1.59 per pound

15.90/1.20 = 13.25 pounds, 6.625 pounds of M&M and 6.625 pounds of Reese

will get 10 pounds which can be sold for total $15.90 with 3 1/4 pounds left over

That's the only way the problem seems to make sense

usually though this type of problem has one of the two less than $1.59 and the other greater than $1.59.

As there is no way to mix the two if to get $1.59 if both are less than $1.59 and get 10 pounds.

for example, if M&M cost $1.20 and Reese cost $2.20, then the problem would be

2.20x + 1.2(10-x) = 1.59(10 = 15.90

2.20x - 1.2x = 15.90- 12

x = 3.9 pounds of Reese mixed with 6.1 pounds of M&M to get a 10 lb mixture costing $15.90

2.2(3.9) + 1.2(6.1) = 15.9

8.58 +7.32 = 15.9