r' + 2 r θ - r - 4 θ +2 =0
r' + 2 (r-2) (θ-1/2) = 0
dr / (r-2) = -(2θ - 1) dθ
ln |r-2| = θ - θ^2 + C1
|r-2| = C e^(θ-θ^2)
Lucy Y.
tutor
I missed the "-" in the middle of typing. This "-" did carry on in the calculation and if you follow the next line, and the result, it is with the "-". Thanks for noticing though! I have fixed that one
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03/08/22
Luke J.
Slight error Lucy Y., when you rearranged the equation of line 2 to line 3, there's a missing negative that wasn't accounted for in moving from one side of the equal sign to the other. I believe it would be 1 - 2θ, not 2θ - 1 Otherwise, your answer is ultimately on route to the right answer!03/08/22