Aricia P. answered 02/28/22
Tutor
2.8
(12)
PHD MATHEMATICS
Solution
When x=-1
g(x-1,y)=( x-1)'2/2(x-1)-y'2
When x= o
g(0+x,y)=( x+0)'2/2(x+0)-y'2
When x= 1
g(1+x,y)= (1+x)'2/2(x+1)-y'2
Lorellei S.
asked 02/28/22The function is: g(x, y) = x2 /(2x − y2) .
Find the equations of the level curves of g at k = −1, 0, 1
Aricia P. answered 02/28/22
PHD MATHEMATICS
Solution
When x=-1
g(x-1,y)=( x-1)'2/2(x-1)-y'2
When x= o
g(0+x,y)=( x+0)'2/2(x+0)-y'2
When x= 1
g(1+x,y)= (1+x)'2/2(x+1)-y'2
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