Math, (Title Must be between 15 and 200 characters)

Question

tell whether the ordered pair is a solution of the linear system

(5,2)

2x-3y=4

2x+8y=11

Answer 1

To solve this, you must insert the ordered pair of (5,2) in which the 5 is represented for the variable x and the 2 is represented for the variable y as so:

(5,2)

(x,y)

Now that we know which is our x and y, we then insert it in the two equations to see if it's a solution.

The two equations we have are:

2x-3y=4

2x+8y=11

So let's work with the top equation first and insert the point of (5, 2):

2x-3y=4 <--- original equation of the first

2(5)-3(2)=4 <--- substitute x with 5 and y with 2, given by explaination from earlier

10-6=4 <---- multiply 2 times 5 and the 3 times 2

4=4 <--- simplify

Since the first equation with the ordered pair matches from the answer to the left to the one on the right, we can say that the ordered pair is a solution to that particular equation. Now let's see if the same ordered pair works for the second equation as so:

2x+8y=11 <---- Original equation of the second

2(5)+8(2)=11 <--- substitute x with 5 and y with 2, given by explaination from earlier

10+16=11 <---- multiply 2 times 5 and the 8 times 2

26=11 <--- simplify

Since 26 does not equal to 11 based on the ordered pair given, we can say that the ordered pair of (5,2) is not a solution to the second equation.

In conclusion the ordered pair (5,2) is not the solution to the linear equations of:

2x-3y=4

2x+8y=11

In order for the ordered pair to work as a solution to the linear equations, the left side of the answer must be correct with the answer on the right for both set of equations.

Hope this helps!!