Use synthetic division to find the quotient and remainder when 2x^3+6x^2−14x+9 is divided by x+3.

Question

Use synthetic division to find the quotient and remainder when 2x^3+6x^2−14x+9 is divided by x+3.

Answer 1

2x^3+6x^2-14x + 9 divided by x+3 = 2x^2 -14 with remainder 51

P(-3) =2(-3)+6(-3)^2-14(-3)+9 = 51

-3| 2 6 -14 9

2 -6

0 -14 42

51