
Yefim S. answered 02/27/22
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- 4 - 4x2 + y2 > 0; 4x2 - y2 < 4; x2 - y2/4 < 1 This is internal part of hyperbola.
- fx = y/(4 - 4x2 + y2)(- 8x) = (- 8xy)/(4 - 4x2 + y2); fxy = - 8x(4 - 4x2 + y2 - 2y2)/(4 - 4x2 + y2)2
-8x(4 - 4x2 - y2)/(4 - 4x2 + y2)2