Daniel B. answered 02/27/22
PhD in Computer Science with 42 years in Computer Research
Initially
F = (x1)∧(¬x1∨x2)∧(x2∨x3)∧(¬x2∨x4)
The first unit clause yields the first assignment x1=T.
After substituting that
F = (x2)∧(x2∨x3)∧(¬x2∨x4)
The new unit clause yields the second assignment x2=T.
After substituting that
F = (T∨x3)∧(x4)
The new unit clause yields the third assignment x4=T.
After substituting that
F = (T∨x3)
There is no assignment to x3, because F is satisfied with any value for x3.