Raymond B. answered 02/24/22
Math, microeconomics or criminal justice
sinx = 0.3 = 3/10
cosx = square root of 1-sin^2x = sqr(1-9/100) = sqr(91/100)
=sqr91/10= about 0.954
tanx = sinx/cosx = (3/10)/(sqr91/10)
= 3/sqr91 = about 0.314
Egeg G.
asked 02/23/22Given that sinθ=0.3 and 0 is in the quadrant, what are cosθ and tanθ? Use the identity sin^2θ+cos^2θ=1 and the basic identities.
Raymond B. answered 02/24/22
Math, microeconomics or criminal justice
sinx = 0.3 = 3/10
cosx = square root of 1-sin^2x = sqr(1-9/100) = sqr(91/100)
=sqr91/10= about 0.954
tanx = sinx/cosx = (3/10)/(sqr91/10)
= 3/sqr91 = about 0.314
Alina T. answered 02/24/22
Math teacher with a passion for knowledge disseminat and learning
If θ is in the first quadrant, we know that both sin and cos are positive.
sin θ is given, and we have the identity sin(θ)2 + cos(θ)2 = 1
So, we can compute cos(θ) by taking the sqrt (1- (sin (θ))2)
Then, we use the formula for tan(θ) = sin(θ)/cos(θ)
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