What is the solution in the interval 0≤θ<2pi

Question

Solve the interval 2sin^2 θ + sin θ - 1 = 0 in the interval 0≤θ<2pi?

Answer 1

Assume x=sin(theta)====> 2x²+x-1=0 x=0.5, -1.25 (not acceptable because it’s not between -1 and 1)

sin(theta)=0.5; theta =30, 180-30=150 degree