Write the equation of a sine function that has the following characteristics. Amplitude: 6 Period: 3pi Phase Shift: 1/5

Question

Amplitude: 5

Period: 6pi

Phase Shift: 1/5

I've tried entering the equation y = 6sin ((2/3)x - 1/15)), but my program says that the 1/15 is incorrect. Can someone help?

Thanks so much in advance!

Answer 1

y = Asin(Bx + C) A = 5, 2π/B = 6π (so B = 1/3)

Phase shift = -C/B. So, -C / (1/3) = 1/5. Therefore, C = -1/15