How do you use parentheses to rewrite the numerical expression 25-4x3+2 to equal 11

Answer 1

25 - 4x^3 + 2 = 11

4x^3 = 16

x^3 = 16/4 = 4

x = the cube root of 4 = about 1.59

but

x^3 -4 = 0 has 3 roots, 3 solutions.

x^3-4 = (x-4^(1/3))(x^2 + x(4)^(2/3) - 4)

set the 2nd factor = 0 and solve for x gives 2 imaginary solutions, a conjugate pair.