Investment in stock

Question

A woman invested $8000 in two stocks. One stock decreased in value by 8% and the other by 30%. If she lost a total of $1300 on these two stocks, how much was invested in the stock that decreased in value by 8%?

Answer 1

.92x + .7(8,000-x) = 8,000- 1,300

.92x-.7x = 6700-5600 = 1100

.22x = 1100

x = 1100/.22 = 100/.02 = $5000 investment lost 8% .08(5000) =$400 loss

8,000-5000 = $3000 investment lost 30%. .3(3000) = $900 loss

400+900= 1300