-8 <= 1 - 3(x-2) < 3
-8 <= 1 -3x + 6 < 3
-8 <= -3x + 5 < 3
-13 <= -3x < -2
13/3 >= x > 2/3
Sean Q.
asked 02/09/22This question is based on Chapter 6.3 Compound Inequalities in the Health Algebra 1 textbook which is a very tricky question that needs to be figured out as soon as possible with some help.
-8 <= 1 - 3(x-2) < 3
-8 <= 1 -3x + 6 < 3
-8 <= -3x + 5 < 3
-13 <= -3x < -2
13/3 >= x > 2/3
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Beth B.
This answer is incorrect. Either you must add 1 and 6 to make 7 and have -3x remain negative OR you can subtract 6 from 1 and make -3x become positive, however, we have a +1 and a +6 after distribution of the -3, so you should end up with -3x + 7, then deal with the inequalities02/11/22