Yefim S. answered • 02/07/22
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Dividing we get: ∫(6x^(2)-4x-25)/(x-2)dx = ∫(6x + 8 - 9/(x - 2))dx = 3x2 + 8x - 9lnIx - 2I + C
Snow W.
asked • 02/07/22Evaluate the indefinite integral:
∫(6x^(2)-4x-25)/(x-2) dx
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Using partial fraction decomposition (long division) gives (6x^(2)-4x-25)/(x-2)=(6x+8) - 9/(x-2), and then
∫ [(6x+8) - 9/(x-2))]dx =3x^2 +8x-9ln|x-2| +C
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