A chemist has 30% and 60% solutions of acid available...

Question

A chemist has 30% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 480 liters of 31% acid solution?

 ____liters of 30% acid

_____ liters of 60% acid

Answer 1

.6x + .3(480-x) = .31(480)

.6x - .3x = .31(480) - .3(480)

.3x = .01(480) = 4.8

x = 4.8/.3 = 16 Liters of 60%

480-x = 464 Liters of 30% to get 480 Liters of 31%

30 is within 1 of 31

60 is within 29 of 31

29/1 = 464/16 = 29