Joy needs to mix a 10% acid solution with a 50% acid solution to create 200 millileters of a 14% solution. ..

Question

Joy needs to mix a 10% acid solution with a 50% acid solution to create 200 millileters of a 14% solution. How many millileters of each solution must Joy use?

Answer: Joy must mix

 _____millileters of 10% solution and

 _____millileters of 50% solution.

Answer 1

.5x + .1(200-x) = .14(200)

.5x -.1x = .14(200)-.1(200)

.4x = .04(200) = 8

x = 8/.4 = 20 ml of 50%

mixed with 180 ml of 10% yields 200 ml of 14%

10 is within 4 of 14

50 is within 36 of 14

36/4 = 9 = 180/20

.5(20) + .1(180) = 10+18= 28 = .14(200)