Write the slope-intercept form of the equation of the line passing through (3, 2) with a slope of 4.

Answer 1

Given a point, (x, y) = (3, 2) and a slope (m) of 4

Start with y = mx + b which is the slope-intercept form for the equation of a line.

Replace y with 2, m with 4 and x with 3 and we get

2 = 4(3) + b,

Now solve for b

2 = 12 + b

Subtract 12 from both sides

-12 = b

So the required equation is y = 4x - 12

Answer 2

Start with point-slope form:

(y - 2) = 4(x - 3)

Simplify and convert to slope-intercept form