y = 3x + 22
2x + 2y = 12
x + y = 6
y = 6-x
6-x = 3x +22
4x = 6-22 = - 16
x = -16/4 = -4
y = 6 --4 = 10
(-4,10) = (x,y) is the solution. there is only one solution: x=-4, y=10
John D.
asked 01/30/22Solve the following system of linear equations by substitution and determine whether the system has one solution, no solution, or an infinite number of solutions. If the system has one solution, find the solution.
y=−3x+22
2x+2y=12
y = 3x + 22
2x + 2y = 12
x + y = 6
y = 6-x
6-x = 3x +22
4x = 6-22 = - 16
x = -16/4 = -4
y = 6 --4 = 10
(-4,10) = (x,y) is the solution. there is only one solution: x=-4, y=10
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