SINIT A.

asked • 01/28/22

The graph of y = x2 is stretched vertically by a factor of 2 and shifted 5 units left and 2 units down. Write an equation for the new graph.

The graph of y = x2 is stretched vertically by a factor of 2 and shifted 5 units left 

     and 2 units down. Write an equation for the new graph. 


1 Expert Answer

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Raymond B. answered • 01/29/22

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y = x^2 stretched vertically by factor of 2 becomes y= 2x^2


shifted left 5 units becomes y = 2(x+5)^2 = 2(x^2 + 10x +25) = 2x^2 + 20x + 50


shifted down 2 units becomes y=2(x+5)^2 - 2 = 2x^2+20x+48


original equation was a parabola with vertex at the origin

final equation is a parabola with vertex at (-5, -2)

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Francis A.

X+y=195 5x+15y=1875 5×+15y=1875 5x+15(195-x)=1875 5x+2925-15x=1875 -10x=-1050 =105 X+y=195 105+y=195 Y=90 Answer would be first mechanic : $105an hr Second mechanic: $90 an hr.
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03/26/22

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