if the 21st and 22nd terms in the expansion of (1+x)^44 are equal. Find the value of x
By binomial expansion, if the 21st and 22nd terms are equal, then
C(44, 20) x^24 = C(44, 21) x^23
Solve for x,
x = C(44, 21)/C(44, 20) = 8/7 <==Answer
find the value of x in the expansion of (1+x)^44
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Robert J. | Certified High School AP Calculus and Physics TeacherCertified High School AP Calculus and Ph...
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Comments
C(44, 20) x^24 = C(44, 21) x^23
For the 20th and 21 st term, it should read, C(44, 20) x^20 = C(44, 21) x^21
44! X^20 44! X^21
------------------------ = ---------------------------
24! 20! 23! 21!
23! 21 20!
-------------- = x = 7/8 (the reciprocal)
24 23! 20!
Not possible to edit comment. It should read the 21st and 22nd term.