How long would it take an object to hit the canyon floor if it were to be accidentally dropped from the skywalk? Use d(t)=16t² for this calculation, and round to nearest tenth of a second.

Answer 1

Grand Canyon varies from 5,000 to 9,000 feet deep

for an object dropped from above, it would reach rock bottom when h(t) = -16t^2 = -9000

t^2 = 9000/16= (900/16)10

t = (30/4)sqr10 = 7.5(3.16) = 23.7 seconds

about 23.7 seconds to reach the canyon floor