Raymond B. answered 01/25/22
Math, microeconomics or criminal justice
standard form: ax^2 + bx + c, c= the y intercept
vertex form: a(x-h)^2 + k where (h,k) = the vertex
factored form: a(x-d)(x-e) where d and e are zeros or x intercepts
convert standard to vertex form:
ax^2 + bx + c
= a(x^2 +bx/a) + c,
complete the square
= a(x^2 + bx/a + (b/2a)^2) + c - a(b/2a)^2
= a(x + b/2a)^2 + c-a(b^2/4a^2)
= a(x+b/2a)^2 + c-(b^2/4a)
= a(x+b/2a)^2 + (4ac-b^2)/4a
where (-b/2a, (4ac-b^2)/4a) is the vertex of the parabola, = maximum of a<0, minimum if a>0
notice the numerator of the y coordinate = the negative of the discriminant
and the x coordinate is the negative of the 1st term of the solution for x using the quadratic formula
x = -b/2a + or - (1/2a)sqr(b^2 - 4ac)
factor form:
a(x-d)(x-e)
= a(x^2 -(d+e)x +de)
=ax^2 -a(d+e)x + ade
where ad+ae = b and ade = c
for standard form ax^2 + bx + c
= ax^2 +(ad+ae)x + ade