Write an equation of the line with a slope of 1/5 that passes through the point (20, 5)

Answer 1

Hello Jean Paul,

The slope-intercept equation of a line is: y = mx + b where m is the slope, b is the y-intercept.

You're already given the slope m, so you can write the equation as: y = (1/5)*x + b

To find b, plug the point you're given in the equation. In the pair (20,5), 20 is the x, 5 is the y so:

5 = (1/5)*20 + b

That means: 5 = 4 + b

Subtract 4 from both sides: b = 1

The equation is now complete: y = (1/5)*x + 1