Gilberto P. answered • 01/22/22
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Experienced high school teacher in STEM disciplines.
If pure antifreeze is 85%, then you want a ratio that would give 30% at 225 gallons. To set that up, we'd say:
(.85)(x) = 225(.3) ((This is the equation that solves for how much anti-freeze we need). So if we solve for x, we get that x = 225(.3)/(.85) or, that you need around ~79 gallons of anti-freeze. Then we can set up an equation for total gallons, as 79 + b = 225. We solve for b, so b = 225 - 79. b = 146 gallons of water.
Gilberto P.
I solved for 225, not 255. If you do the work. For 255, just replace 225 with that. 255(.3)/.85 = 90 (anti freeze) 255-90 = 165 (water).
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01/22/22
Thomas Z.
thank you very much. i do have another question for you, A chemical company makes two brands of antifreeze. The first brand is 55% pure antifreeze, and the second brand is 85% pure antifreeze. In order to obtain 180 gallons of a mixture that contains 75% pure antifreeze, how many gallons of each brand of antifreeze must be used?
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01/23/22
Thomas Z.
not to sure why buy when i put the answer in ALEKS is came up as wrong01/22/22