The sum of three numbers is 133. The third number is 4 times the second. The first number is 7 more than the second. What are the numbers?

Question

The sum of three numbers is 133

. The third number is 4

 times the second. The first number is 7

 more than the second.What are the numbers? 

Answer 1

x + y + z = 133

x = 7+y

z = 4y

4y + y + 7+y = 133

6y = 133-7 = 126

y = 126/6 = 21

x= 21+7 = 28

z = 4(21) = 84

28+21+84 = 133