if I ended a reaction with 50 grams of so3, how many grams of s8 did I begin with

Answer 1

In order to begin with S8 and end up with SO3, the reaction would probably be the following:

S₈(s) + 12O₂(g) ==> 8SO₃(g) ... balanced equation

molar mass SO3 = 80.06 g/mol

molar mass S8 = 256.5 g/mol

Use dimensional analysis to solve...

50 g SO₃ x 1 mol SO₃ / 80.06 g x 1 mol S₈ / 8 mols SO₃ x 256.5 g S₈ / mol = 20 g S₈