Please help me :)

Question

What is an equation of the line that is perpendicular to the line y=-2/3x-1 and passes through the point (-6,4).

Answer 1

y = (-2/3)x - 1 is a line with a perpendicular line with slope = negative inverse = 3/2. take -2/3, change its sign and flip the fraction upside down

that perpendicular line's equation is y= (3/2)x + b where b= the y intercept

plug in the point (-6,4) to solve for b

4 = (3/2)(-6) + b

b = 4 +9 = 13

y = (3/2)x + 13 is the perpendicular line through the given point