I can't figure out how to do the D=RT on this problem

Question

Solve.  Use x and y for your variables.  Write your equations in the same order in which they are described.  Enter your answer in order from least to greatest.

An airplane that can travel 760 kph in still air can make a 2000 km journey with the wind in the same amount of time it takes to fly 1800 km against the wind.

First Equation - 

 

Second Equation - 

 

Find the speed of the wind.

The wind speed is 

. 

Answer 1

at 760 kph goes 2,000 km in still air

in the same time that it goes 1,800 km against the wind

d = rt

distance= rates of speed times time traveled

t = d/r

t = 2000/760 = about 2.63 hours

t = 1800/(684) = 2.63 hours

if you want x and y variables use y for time t, and x for speed against the wind, although you could assign x and y to other variables

1st equation 2000/760 = time = y

2nd equation 1800/x = time = y where x = speed against the wind

set the time equal y = y, 2000/760 = 1800/x

2000/760 = 1800/x

x = 1800(760)/2000 = 18(760)/20 = 9(76) = 684 = speed against the wind

wind speed = 760- 684 = 76 kph = wind speed

y = time = 2000/760 = about 2.63 hours = 1800/684