Determine the amount of pizza and sodas sold

Question

At the football game they sold $4 pizzas and $2 sodas, which made the school $260. The number of sodas sold was 5 more than 3 times the number of pizzas sold.

Answer 1

Hi Abby. Below is the broken-down problem.

Step 1: Label your variables.

p- # of pizzas sold

s- # of sodas sold

Step 2: Create Equations. Since we have 2 variables, we need 2 equations.

4 pizzas + 2 Sodas = 260

4p+ 2s = 260

3 pizzas + 5 = Sodas

3p+ 5= s

Step 3: Solve the Equations

Let's substitute the s value

4p + 2s = 260

3p + 5 = s

4p + 2(3p + 5) = 260

4p + 6p +10 =260

10 p + 10 = 260

10p= 250

p= 25

Substitute the P-value back into the original equation

3p + 5 = s

3(25) + 5 = s

80=s

s=80

Step 4: Do a quick check by plugging both values into the original equations to make sure both sides are equal.

3p + 5 = s 4p + 2s = 260

3(25) + 5 = 80 4(25)+ 2(80)= 260

80 = 80 260 = 260

There were 25 pizzas sold and 80 sodas. I hope this helps.

Answer 2

4P + 2S = 260

S = 5 + 3P

4P + 2(5+3P) = 260

4P + 10 + 6P = 260

10P = 260-10 = 250

P = 250/10 = 25 pizzas

S = 5+3P = 5+3(25) = 5+ 75 = 80 sodas

4(25) +2(80) = 100+160 + $260 total

25 pizzas and 80 sodas sold